Metamath Proof Explorer


Theorem negsubdi2d

Description: Distribution of negative over subtraction. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses negidd.1 ⊢ φ → A ∈ ℂ
pncand.2 ⊢ φ → B ∈ ℂ
Assertion negsubdi2d ⊢ φ → − A − B = B − A

Proof

Step Hyp Ref Expression
1 negidd.1 ⊢ φ → A ∈ ℂ
2 pncand.2 ⊢ φ → B ∈ ℂ
3 negsubdi2 ⊢ A ∈ ℂ ∧ B ∈ ℂ → − A − B = B − A
4 1 2 3 syl2anc ⊢ φ → − A − B = B − A