Metamath Proof Explorer


Theorem nfrexd

Description: Deduction version of nfrex . Usage of this theorem is discouraged because it depends on ax-13 . See nfrexdw for a version with a disjoint variable condition, but not requiring ax-13 . (Contributed by Mario Carneiro, 14-Oct-2016) (New usage is discouraged.)

Ref Expression
Hypotheses nfrald.1 yφ
nfrald.2 φ_xA
nfrald.3 φxψ
Assertion nfrexd φxyAψ

Proof

Step Hyp Ref Expression
1 nfrald.1 yφ
2 nfrald.2 φ_xA
3 nfrald.3 φxψ
4 dfrex2 yAψ¬yA¬ψ
5 3 nfnd φx¬ψ
6 1 2 5 nfrald φxyA¬ψ
7 6 nfnd φx¬yA¬ψ
8 4 7 nfxfrd φxyAψ