Metamath Proof Explorer


Theorem noetasuplem1

Description: Lemma for noeta . Establish that our final surreal really is a surreal. (Contributed by Scott Fenton, 6-Dec-2021)

Ref Expression
Hypotheses noetasuplem.1 ⊢ S = if ∃ x ∈ A ∀ y ∈ A ¬ x < s y ι x ∈ A | ∀ y ∈ A ¬ x < s y ∪ dom ⁡ ι x ∈ A | ∀ y ∈ A ¬ x < s y 2 𝑜 g ∈ y | ∃ u ∈ A y ∈ dom ⁡ u ∧ ∀ v ∈ A ¬ v < s u → u ↾ suc ⁡ y = v ↾ suc ⁡ y ⟼ ι x | ∃ u ∈ A g ∈ dom ⁡ u ∧ ∀ v ∈ A ¬ v < s u → u ↾ suc ⁡ g = v ↾ suc ⁡ g ∧ u ⁡ g = x
noetasuplem.2 ⊢ Z = S ∪ suc ⁡ ⋃ bday B ∖ dom ⁡ S × 1 𝑜
Assertion noetasuplem1 ⊢ A ⊆ No ∧ A ∈ V ∧ B ∈ V → Z ∈ No

Proof

Step Hyp Ref Expression
1 noetasuplem.1 ⊢ S = if ∃ x ∈ A ∀ y ∈ A ¬ x < s y ι x ∈ A | ∀ y ∈ A ¬ x < s y ∪ dom ⁡ ι x ∈ A | ∀ y ∈ A ¬ x < s y 2 𝑜 g ∈ y | ∃ u ∈ A y ∈ dom ⁡ u ∧ ∀ v ∈ A ¬ v < s u → u ↾ suc ⁡ y = v ↾ suc ⁡ y ⟼ ι x | ∃ u ∈ A g ∈ dom ⁡ u ∧ ∀ v ∈ A ¬ v < s u → u ↾ suc ⁡ g = v ↾ suc ⁡ g ∧ u ⁡ g = x
2 noetasuplem.2 ⊢ Z = S ∪ suc ⁡ ⋃ bday B ∖ dom ⁡ S × 1 𝑜
3 1 nosupno ⊢ A ⊆ No ∧ A ∈ V → S ∈ No
4 3 3adant3 ⊢ A ⊆ No ∧ A ∈ V ∧ B ∈ V → S ∈ No
5 bdayimaon ⊢ B ∈ V → suc ⁡ ⋃ bday B ∈ On
6 5 3ad2ant3 ⊢ A ⊆ No ∧ A ∈ V ∧ B ∈ V → suc ⁡ ⋃ bday B ∈ On
7 1oex ⊢ 1 𝑜 ∈ V
8 7 prid1 ⊢ 1 𝑜 ∈ 1 𝑜 2 𝑜
9 8 noextendseq ⊢ S ∈ No ∧ suc ⁡ ⋃ bday B ∈ On → S ∪ suc ⁡ ⋃ bday B ∖ dom ⁡ S × 1 𝑜 ∈ No
10 4 6 9 syl2anc ⊢ A ⊆ No ∧ A ∈ V ∧ B ∈ V → S ∪ suc ⁡ ⋃ bday B ∖ dom ⁡ S × 1 𝑜 ∈ No
11 2 10 eqeltrid ⊢ A ⊆ No ∧ A ∈ V ∧ B ∈ V → Z ∈ No