Metamath Proof Explorer


Theorem nsb

Description: Any substitution in an always false formula is false. (Contributed by Steven Nguyen, 3-May-2023)

Ref Expression
Assertion nsb ⊢ ∀ x ¬ φ → ¬ t x φ

Proof

Step Hyp Ref Expression
1 alnex ⊢ ∀ x ¬ φ ↔ ¬ ∃ x φ
2 1 biimpi ⊢ ∀ x ¬ φ → ¬ ∃ x φ
3 spsbe ⊢ t x φ → ∃ x φ
4 2 3 nsyl ⊢ ∀ x ¬ φ → ¬ t x φ