Metamath Proof Explorer


Theorem nssdmovg

Description: The value of an operation outside its domain. (Contributed by Alexander van der Vekens, 7-Sep-2017)

Ref Expression
Assertion nssdmovg ⊢ dom ⁡ F ⊆ R × S ∧ ¬ A ∈ R ∧ B ∈ S → A F B = ∅

Proof

Step Hyp Ref Expression
1 df-ov ⊢ A F B = F ⁡ A B
2 ssel2 ⊢ dom ⁡ F ⊆ R × S ∧ A B ∈ dom ⁡ F → A B ∈ R × S
3 opelxp ⊢ A B ∈ R × S ↔ A ∈ R ∧ B ∈ S
4 2 3 sylib ⊢ dom ⁡ F ⊆ R × S ∧ A B ∈ dom ⁡ F → A ∈ R ∧ B ∈ S
5 4 stoic1a ⊢ dom ⁡ F ⊆ R × S ∧ ¬ A ∈ R ∧ B ∈ S → ¬ A B ∈ dom ⁡ F
6 ndmfv ⊢ ¬ A B ∈ dom ⁡ F → F ⁡ A B = ∅
7 5 6 syl ⊢ dom ⁡ F ⊆ R × S ∧ ¬ A ∈ R ∧ B ∈ S → F ⁡ A B = ∅
8 1 7 eqtrid ⊢ dom ⁡ F ⊆ R × S ∧ ¬ A ∈ R ∧ B ∈ S → A F B = ∅