Metamath Proof Explorer


Theorem nthruz

Description: The sequence NN , NN0 , and ZZ forms a chain of proper subsets. In each case the proper subset relationship is shown by demonstrating a number that belongs to one set but not the other. We show that zero belongs to NN0 but not NN and minus one belongs to ZZ but not NN0 . This theorem refines the chain of proper subsets nthruc . (Contributed by NM, 9-May-2004)

Ref Expression
Assertion nthruz ⊢ ℕ ⊂ ℕ 0 ∧ ℕ 0 ⊂ ℤ

Proof

Step Hyp Ref Expression
1 nnssnn0 ⊢ ℕ ⊆ ℕ 0
2 0nn0 ⊢ 0 ∈ ℕ 0
3 0nnn ⊢ ¬ 0 ∈ ℕ
4 2 3 pm3.2i ⊢ 0 ∈ ℕ 0 ∧ ¬ 0 ∈ ℕ
5 ssnelpss ⊢ ℕ ⊆ ℕ 0 → 0 ∈ ℕ 0 ∧ ¬ 0 ∈ ℕ → ℕ ⊂ ℕ 0
6 1 4 5 mp2 ⊢ ℕ ⊂ ℕ 0
7 nn0ssz ⊢ ℕ 0 ⊆ ℤ
8 neg1z ⊢ − 1 ∈ ℤ
9 neg1lt0 ⊢ − 1 < 0
10 nn0nlt0 ⊢ − 1 ∈ ℕ 0 → ¬ − 1 < 0
11 9 10 mt2 ⊢ ¬ − 1 ∈ ℕ 0
12 8 11 pm3.2i ⊢ − 1 ∈ ℤ ∧ ¬ − 1 ∈ ℕ 0
13 ssnelpss ⊢ ℕ 0 ⊆ ℤ → − 1 ∈ ℤ ∧ ¬ − 1 ∈ ℕ 0 → ℕ 0 ⊂ ℤ
14 7 12 13 mp2 ⊢ ℕ 0 ⊂ ℤ
15 6 14 pm3.2i ⊢ ℕ ⊂ ℕ 0 ∧ ℕ 0 ⊂ ℤ