Metamath Proof Explorer


Theorem nthruz

Description: The sequence NN , NN0 , and ZZ forms a chain of proper subsets. In each case the proper subset relationship is shown by demonstrating a number that belongs to one set but not the other. We show that zero belongs to NN0 but not NN and minus one belongs to ZZ but not NN0 . This theorem refines the chain of proper subsets nthruc . (Contributed by NM, 9-May-2004)

Ref Expression
Assertion nthruz ( ℕ ⊊ ℕ0 ∧ ℕ0 ⊊ ℤ )

Proof

Step Hyp Ref Expression
1 nnssnn0 ℕ ⊆ ℕ0
2 0nn0 0 ∈ ℕ0
3 0nnn ¬ 0 ∈ ℕ
4 2 3 pm3.2i ( 0 ∈ ℕ0 ∧ ¬ 0 ∈ ℕ )
5 ssnelpss ( ℕ ⊆ ℕ0 → ( ( 0 ∈ ℕ0 ∧ ¬ 0 ∈ ℕ ) → ℕ ⊊ ℕ0 ) )
6 1 4 5 mp2 ℕ ⊊ ℕ0
7 nn0ssz 0 ⊆ ℤ
8 neg1z - 1 ∈ ℤ
9 neg1lt0 - 1 < 0
10 nn0nlt0 ( - 1 ∈ ℕ0 → ¬ - 1 < 0 )
11 9 10 mt2 ¬ - 1 ∈ ℕ0
12 8 11 pm3.2i ( - 1 ∈ ℤ ∧ ¬ - 1 ∈ ℕ0 )
13 ssnelpss ( ℕ0 ⊆ ℤ → ( ( - 1 ∈ ℤ ∧ ¬ - 1 ∈ ℕ0 ) → ℕ0 ⊊ ℤ ) )
14 7 12 13 mp2 0 ⊊ ℤ
15 6 14 pm3.2i ( ℕ ⊊ ℕ0 ∧ ℕ0 ⊊ ℤ )