Metamath Proof Explorer


Theorem opnneir

Description: If something is true for an open neighborhood, it must be true for a neighborhood. (Contributed by Zhi Wang, 31-Aug-2024)

Ref Expression
Hypothesis opnneir.1 ⊢ φ → J ∈ Top
Assertion opnneir ⊢ φ → ∃ x ∈ J S ⊆ x ∧ ψ → ∃ x ∈ nei ⁡ J ⁡ S ψ

Proof

Step Hyp Ref Expression
1 opnneir.1 ⊢ φ → J ∈ Top
2 anass ⊢ x ∈ J ∧ S ⊆ x ∧ ψ ↔ x ∈ J ∧ S ⊆ x ∧ ψ
3 opnneiss ⊢ J ∈ Top ∧ x ∈ J ∧ S ⊆ x → x ∈ nei ⁡ J ⁡ S
4 3 3expib ⊢ J ∈ Top → x ∈ J ∧ S ⊆ x → x ∈ nei ⁡ J ⁡ S
5 4 anim1d ⊢ J ∈ Top → x ∈ J ∧ S ⊆ x ∧ ψ → x ∈ nei ⁡ J ⁡ S ∧ ψ
6 2 5 biimtrrid ⊢ J ∈ Top → x ∈ J ∧ S ⊆ x ∧ ψ → x ∈ nei ⁡ J ⁡ S ∧ ψ
7 6 reximdv2 ⊢ J ∈ Top → ∃ x ∈ J S ⊆ x ∧ ψ → ∃ x ∈ nei ⁡ J ⁡ S ψ
8 1 7 syl ⊢ φ → ∃ x ∈ J S ⊆ x ∧ ψ → ∃ x ∈ nei ⁡ J ⁡ S ψ