Metamath Proof Explorer


Theorem oppcco

Description: Composition in the opposite category. (Contributed by Mario Carneiro, 2-Jan-2017)

Ref Expression
Hypotheses oppcco.b ⊢ B = Base C
oppcco.c ⊢ · ˙ = comp ⁡ C
oppcco.o ⊢ O = oppCat ⁡ C
oppcco.x ⊢ φ → X ∈ B
oppcco.y ⊢ φ → Y ∈ B
oppcco.z ⊢ φ → Z ∈ B
Assertion oppcco ⊢ φ → G X Y comp ⁡ O Z F = F Z Y · ˙ X G

Proof

Step Hyp Ref Expression
1 oppcco.b ⊢ B = Base C
2 oppcco.c ⊢ · ˙ = comp ⁡ C
3 oppcco.o ⊢ O = oppCat ⁡ C
4 oppcco.x ⊢ φ → X ∈ B
5 oppcco.y ⊢ φ → Y ∈ B
6 oppcco.z ⊢ φ → Z ∈ B
7 1 2 3 4 5 6 oppccofval ⊢ φ → X Y comp ⁡ O Z = tpos Z Y · ˙ X
8 7 oveqd ⊢ φ → G X Y comp ⁡ O Z F = G tpos Z Y · ˙ X F
9 ovtpos ⊢ G tpos Z Y · ˙ X F = F Z Y · ˙ X G
10 8 9 eqtrdi ⊢ φ → G X Y comp ⁡ O Z F = F Z Y · ˙ X G