Metamath Proof Explorer


Theorem oppcco

Description: Composition in the opposite category. (Contributed by Mario Carneiro, 2-Jan-2017)

Ref Expression
Hypotheses oppcco.b B=BaseC
oppcco.c ·˙=compC
oppcco.o O=oppCatC
oppcco.x φXB
oppcco.y φYB
oppcco.z φZB
Assertion oppcco φGXYcompOZF=FZY·˙XG

Proof

Step Hyp Ref Expression
1 oppcco.b B=BaseC
2 oppcco.c ·˙=compC
3 oppcco.o O=oppCatC
4 oppcco.x φXB
5 oppcco.y φYB
6 oppcco.z φZB
7 1 2 3 4 5 6 oppccofval φXYcompOZ=tposZY·˙X
8 7 oveqd φGXYcompOZF=GtposZY·˙XF
9 ovtpos GtposZY·˙XF=FZY·˙XG
10 8 9 eqtrdi φGXYcompOZF=FZY·˙XG