Metamath Proof Explorer


Theorem oppne2

Description: Points lying on opposite sides of a line cannot be on the line. (Contributed by Thierry Arnoux, 3-Mar-2020)

Ref Expression
Hypotheses hpg.p ⊢ P = Base G
hpg.d ⊢ - ˙ = dist ⁡ G
hpg.i ⊢ I = Itv ⁡ G
hpg.o ⊢ O = a b | a ∈ P ∖ D ∧ b ∈ P ∖ D ∧ ∃ t ∈ D t ∈ a I b
opphl.l ⊢ L = Line 𝒢 ⁡ G
opphl.d ⊢ φ → D ∈ ran ⁡ L
opphl.g ⊢ φ → G ∈ 𝒢 Tarski
oppcom.a ⊢ φ → A ∈ P
oppcom.b ⊢ φ → B ∈ P
oppcom.o ⊢ φ → A O B
Assertion oppne2 ⊢ φ → ¬ B ∈ D

Proof

Step Hyp Ref Expression
1 hpg.p ⊢ P = Base G
2 hpg.d ⊢ - ˙ = dist ⁡ G
3 hpg.i ⊢ I = Itv ⁡ G
4 hpg.o ⊢ O = a b | a ∈ P ∖ D ∧ b ∈ P ∖ D ∧ ∃ t ∈ D t ∈ a I b
5 opphl.l ⊢ L = Line 𝒢 ⁡ G
6 opphl.d ⊢ φ → D ∈ ran ⁡ L
7 opphl.g ⊢ φ → G ∈ 𝒢 Tarski
8 oppcom.a ⊢ φ → A ∈ P
9 oppcom.b ⊢ φ → B ∈ P
10 oppcom.o ⊢ φ → A O B
11 1 2 3 4 8 9 islnopp ⊢ φ → A O B ↔ ¬ A ∈ D ∧ ¬ B ∈ D ∧ ∃ t ∈ D t ∈ A I B
12 10 11 mpbid ⊢ φ → ¬ A ∈ D ∧ ¬ B ∈ D ∧ ∃ t ∈ D t ∈ A I B
13 12 simplrd ⊢ φ → ¬ B ∈ D