Metamath Proof Explorer


Theorem oppr2idl

Description: Two sided ideal of the opposite ring. (Contributed by Thierry Arnoux, 9-Mar-2025)

Ref Expression
Hypotheses oppreqg.o ⊢ O = opp r ⁡ R
oppr2idl.2 ⊢ φ → R ∈ Ring
Assertion oppr2idl ⊢ φ → 2Ideal ⁡ R = 2Ideal ⁡ O

Proof

Step Hyp Ref Expression
1 oppreqg.o ⊢ O = opp r ⁡ R
2 oppr2idl.2 ⊢ φ → R ∈ Ring
3 incom ⊢ LIdeal ⁡ R ∩ LIdeal ⁡ O = LIdeal ⁡ O ∩ LIdeal ⁡ R
4 1 2 opprlidlabs ⊢ φ → LIdeal ⁡ R = LIdeal ⁡ opp r ⁡ O
5 4 ineq2d ⊢ φ → LIdeal ⁡ O ∩ LIdeal ⁡ R = LIdeal ⁡ O ∩ LIdeal ⁡ opp r ⁡ O
6 3 5 eqtrid ⊢ φ → LIdeal ⁡ R ∩ LIdeal ⁡ O = LIdeal ⁡ O ∩ LIdeal ⁡ opp r ⁡ O
7 eqid ⊢ LIdeal ⁡ R = LIdeal ⁡ R
8 eqid ⊢ LIdeal ⁡ O = LIdeal ⁡ O
9 eqid ⊢ 2Ideal ⁡ R = 2Ideal ⁡ R
10 7 1 8 9 2idlval ⊢ 2Ideal ⁡ R = LIdeal ⁡ R ∩ LIdeal ⁡ O
11 eqid ⊢ opp r ⁡ O = opp r ⁡ O
12 eqid ⊢ LIdeal ⁡ opp r ⁡ O = LIdeal ⁡ opp r ⁡ O
13 eqid ⊢ 2Ideal ⁡ O = 2Ideal ⁡ O
14 8 11 12 13 2idlval ⊢ 2Ideal ⁡ O = LIdeal ⁡ O ∩ LIdeal ⁡ opp r ⁡ O
15 6 10 14 3eqtr4g ⊢ φ → 2Ideal ⁡ R = 2Ideal ⁡ O