Metamath Proof Explorer


Theorem ordtopconn

Description: An ordinal topology is connected. (Contributed by Chen-Pang He, 1-Nov-2015)

Ref Expression
Assertion ordtopconn ⊢ Ord ⁡ J → J ∈ Top ↔ J ∈ Conn

Proof

Step Hyp Ref Expression
1 ordtop ⊢ Ord ⁡ J → J ∈ Top ↔ J ≠ ⋃ J
2 onsucconn ⊢ ⋃ J ∈ On → suc ⁡ ⋃ J ∈ Conn
3 2 ordtoplem ⊢ Ord ⁡ J → J ≠ ⋃ J → J ∈ Conn
4 1 3 sylbid ⊢ Ord ⁡ J → J ∈ Top → J ∈ Conn
5 conntop ⊢ J ∈ Conn → J ∈ Top
6 4 5 impbid1 ⊢ Ord ⁡ J → J ∈ Top ↔ J ∈ Conn