Metamath Proof Explorer


Theorem ordtypeon

Description: A proper class with a set-like well-ordering is isomorphic to the proper class of all ordinal numbers. (Contributed by BTernaryTau, 9-Jun-2026)

Ref Expression
Hypothesis ordtypeon.1 ⊢ F = OrdIso R A
Assertion ordtypeon ⊢ R We A ∧ R Se A ∧ ¬ A ∈ V → F Isom E , R On A

Proof

Step Hyp Ref Expression
1 ordtypeon.1 ⊢ F = OrdIso R A
2 1 ordtype ⊢ R We A ∧ R Se A → F Isom E , R dom ⁡ F A
3 2 3adant3 ⊢ R We A ∧ R Se A ∧ ¬ A ∈ V → F Isom E , R dom ⁡ F A
4 1 oicl ⊢ Ord ⁡ dom ⁡ F
5 isof1o ⊢ F Isom E , R dom ⁡ F A → F : dom ⁡ F ⟶ 1-1 onto A
6 f1ovv ⊢ F : dom ⁡ F ⟶ 1-1 onto A → dom ⁡ F ∈ V ↔ A ∈ V
7 2 5 6 3syl ⊢ R We A ∧ R Se A → dom ⁡ F ∈ V ↔ A ∈ V
8 7 notbid ⊢ R We A ∧ R Se A → ¬ dom ⁡ F ∈ V ↔ ¬ A ∈ V
9 8 biimp3ar ⊢ R We A ∧ R Se A ∧ ¬ A ∈ V → ¬ dom ⁡ F ∈ V
10 ordprcon ⊢ Ord ⁡ dom ⁡ F ∧ ¬ dom ⁡ F ∈ V → dom ⁡ F = On
11 4 9 10 sylancr ⊢ R We A ∧ R Se A ∧ ¬ A ∈ V → dom ⁡ F = On
12 isoeq4 ⊢ dom ⁡ F = On → F Isom E , R dom ⁡ F A ↔ F Isom E , R On A
13 11 12 syl ⊢ R We A ∧ R Se A ∧ ¬ A ∈ V → F Isom E , R dom ⁡ F A ↔ F Isom E , R On A
14 3 13 mpbid ⊢ R We A ∧ R Se A ∧ ¬ A ∈ V → F Isom E , R On A