Metamath Proof Explorer


Theorem p1val

Description: Value of poset zero. (Contributed by NM, 22-Oct-2011)

Ref Expression
Hypotheses p1val.b ⊢ B = Base K
p1val.u ⊢ U = lub ⁡ K
p1val.t ⊢ 1 ˙ = 1. ⁡ K
Assertion p1val ⊢ K ∈ V → 1 ˙ = U ⁡ B

Proof

Step Hyp Ref Expression
1 p1val.b ⊢ B = Base K
2 p1val.u ⊢ U = lub ⁡ K
3 p1val.t ⊢ 1 ˙ = 1. ⁡ K
4 elex ⊢ K ∈ V → K ∈ V
5 fveq2 ⊢ k = K → lub ⁡ k = lub ⁡ K
6 5 2 eqtr4di ⊢ k = K → lub ⁡ k = U
7 fveq2 ⊢ k = K → Base k = Base K
8 7 1 eqtr4di ⊢ k = K → Base k = B
9 6 8 fveq12d ⊢ k = K → lub ⁡ k ⁡ Base k = U ⁡ B
10 df-p1 ⊢ 1. = k ∈ V ⟼ lub ⁡ k ⁡ Base k
11 fvex ⊢ U ⁡ B ∈ V
12 9 10 11 fvmpt ⊢ K ∈ V → 1. ⁡ K = U ⁡ B
13 3 12 eqtrid ⊢ K ∈ V → 1 ˙ = U ⁡ B
14 4 13 syl ⊢ K ∈ V → 1 ˙ = U ⁡ B