Metamath Proof Explorer


Theorem partim2

Description: Disjoint relation on its natural domain implies an equivalence relation on the cosets of the relation, on its natural domain, cf. partim . Lemma for petlem . (Contributed by Peter Mazsa, 17-Sep-2021)

Ref Expression
Assertion partim2 ⊢ Disj R ∧ dom ⁡ R / R = A → EqvRel ≀ R ∧ dom ⁡ ≀ R / ≀ R = A

Proof

Step Hyp Ref Expression
1 disjim ⊢ Disj R → EqvRel ≀ R
2 1 adantr ⊢ Disj R ∧ dom ⁡ R / R = A → EqvRel ≀ R
3 disjdmqseq ⊢ Disj R → dom ⁡ R / R = A ↔ dom ⁡ ≀ R / ≀ R = A
4 3 biimpa ⊢ Disj R ∧ dom ⁡ R / R = A → dom ⁡ ≀ R / ≀ R = A
5 2 4 jca ⊢ Disj R ∧ dom ⁡ R / R = A → EqvRel ≀ R ∧ dom ⁡ ≀ R / ≀ R = A