Metamath Proof Explorer


Theorem pfxnndmnd

Description: The value of a prefix operation for out-of-domain arguments. (This is due to our definition of function values for out-of-domain arguments, see ndmfv ). (Contributed by AV, 3-Dec-2022) (New usage is discouraged.)

Ref Expression
Assertion pfxnndmnd ⊢ ¬ S ∈ V ∧ L ∈ ℕ 0 → S prefix L = ∅

Proof

Step Hyp Ref Expression
1 df-pfx ⊢ prefix = s ∈ V , l ∈ ℕ 0 ⟼ s substr 0 l
2 1 mpondm0 ⊢ ¬ S ∈ V ∧ L ∈ ℕ 0 → S prefix L = ∅