Metamath Proof Explorer


Theorem pjeq

Description: Equality with a projection. (Contributed by NM, 20-Jan-2007) (Revised by Mario Carneiro, 15-May-2014) (New usage is discouraged.)

Ref Expression
Assertion pjeq HCAprojHA=BBHxHA=B+x

Proof

Step Hyp Ref Expression
1 pjhth HCH+H=
2 1 eleq2d HCAH+HA
3 2 biimpar HCAAH+H
4 pjpreeq HCAH+HprojHA=BBHxHA=B+x
5 3 4 syldan HCAprojHA=BBHxHA=B+x