Metamath Proof Explorer


Theorem pm14.24

Description: Theorem *14.24 in WhiteheadRussell p. 191. (Contributed by Andrew Salmon, 12-Jul-2011)

Ref Expression
Assertion pm14.24 ⊢ ∃! x φ → ∀ y [˙y / x]˙ φ ↔ y = ι x | φ

Proof

Step Hyp Ref Expression
1 nfeu1 ⊢ Ⅎ x ∃! x φ
2 nfsbc1v ⊢ Ⅎ x [˙y / x]˙ φ
3 pm14.12 ⊢ ∃! x φ → ∀ x ∀ y φ ∧ [˙y / x]˙ φ → x = y
4 3 19.21bbi ⊢ ∃! x φ → φ ∧ [˙y / x]˙ φ → x = y
5 4 ancomsd ⊢ ∃! x φ → [˙y / x]˙ φ ∧ φ → x = y
6 5 expdimp ⊢ ∃! x φ ∧ [˙y / x]˙ φ → φ → x = y
7 pm13.13b ⊢ [˙y / x]˙ φ ∧ x = y → φ
8 7 ex ⊢ [˙y / x]˙ φ → x = y → φ
9 8 adantl ⊢ ∃! x φ ∧ [˙y / x]˙ φ → x = y → φ
10 6 9 impbid ⊢ ∃! x φ ∧ [˙y / x]˙ φ → φ ↔ x = y
11 10 ex ⊢ ∃! x φ → [˙y / x]˙ φ → φ ↔ x = y
12 1 2 11 alrimd ⊢ ∃! x φ → [˙y / x]˙ φ → ∀ x φ ↔ x = y
13 iotaval ⊢ ∀ x φ ↔ x = y → ι x | φ = y
14 13 eqcomd ⊢ ∀ x φ ↔ x = y → y = ι x | φ
15 12 14 syl6 ⊢ ∃! x φ → [˙y / x]˙ φ → y = ι x | φ
16 iota4 ⊢ ∃! x φ → [˙ ι x | φ / x]˙ φ
17 dfsbcq ⊢ y = ι x | φ → [˙y / x]˙ φ ↔ [˙ ι x | φ / x]˙ φ
18 16 17 syl5ibrcom ⊢ ∃! x φ → y = ι x | φ → [˙y / x]˙ φ
19 15 18 impbid ⊢ ∃! x φ → [˙y / x]˙ φ ↔ y = ι x | φ
20 19 alrimiv ⊢ ∃! x φ → ∀ y [˙y / x]˙ φ ↔ y = ι x | φ