Metamath Proof Explorer


Theorem pncan3d

Description: Subtraction and addition of equals. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses negidd.1 ⊢ φ → A ∈ ℂ
pncand.2 ⊢ φ → B ∈ ℂ
Assertion pncan3d ⊢ φ → A + B - A = B

Proof

Step Hyp Ref Expression
1 negidd.1 ⊢ φ → A ∈ ℂ
2 pncand.2 ⊢ φ → B ∈ ℂ
3 pncan3 ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B - A = B
4 1 2 3 syl2anc ⊢ φ → A + B - A = B