Metamath Proof Explorer


Theorem pr2cv

Description: If an unordered pair is equinumerous to ordinal two, then both parts are sets. (Contributed by RP, 8-Oct-2023)

Ref Expression
Assertion pr2cv ⊢ A B ≈ 2 𝑜 → A ∈ V ∧ B ∈ V

Proof

Step Hyp Ref Expression
1 en2 ⊢ A B ≈ 2 𝑜 → ∃ x ∃ y A B = x y
2 breq1 ⊢ A B = x y → A B ≈ 2 𝑜 ↔ x y ≈ 2 𝑜
3 vex ⊢ x ∈ V
4 vex ⊢ y ∈ V
5 pr2ne ⊢ x ∈ V ∧ y ∈ V → x y ≈ 2 𝑜 ↔ x ≠ y
6 5 el2v ⊢ x y ≈ 2 𝑜 ↔ x ≠ y
7 6 biimpi ⊢ x y ≈ 2 𝑜 → x ≠ y
8 preq12nebg ⊢ x ∈ V ∧ y ∈ V ∧ x ≠ y → x y = A B ↔ x = A ∧ y = B ∨ x = B ∧ y = A
9 eqvisset ⊢ x = A → A ∈ V
10 eqvisset ⊢ y = B → B ∈ V
11 9 10 anim12i ⊢ x = A ∧ y = B → A ∈ V ∧ B ∈ V
12 eqvisset ⊢ x = B → B ∈ V
13 eqvisset ⊢ y = A → A ∈ V
14 12 13 anim12ci ⊢ x = B ∧ y = A → A ∈ V ∧ B ∈ V
15 11 14 jaoi ⊢ x = A ∧ y = B ∨ x = B ∧ y = A → A ∈ V ∧ B ∈ V
16 8 15 biimtrdi ⊢ x ∈ V ∧ y ∈ V ∧ x ≠ y → x y = A B → A ∈ V ∧ B ∈ V
17 3 4 7 16 mp3an12i ⊢ x y ≈ 2 𝑜 → x y = A B → A ∈ V ∧ B ∈ V
18 17 com12 ⊢ x y = A B → x y ≈ 2 𝑜 → A ∈ V ∧ B ∈ V
19 18 eqcoms ⊢ A B = x y → x y ≈ 2 𝑜 → A ∈ V ∧ B ∈ V
20 2 19 sylbid ⊢ A B = x y → A B ≈ 2 𝑜 → A ∈ V ∧ B ∈ V
21 20 exlimivv ⊢ ∃ x ∃ y A B = x y → A B ≈ 2 𝑜 → A ∈ V ∧ B ∈ V
22 1 21 mpcom ⊢ A B ≈ 2 𝑜 → A ∈ V ∧ B ∈ V