Metamath Proof Explorer


Theorem prlngpln

Description: Two parallel lines are on a common plane. (Contributed by Thierry Arnoux, 5-Jul-2026)

Ref Expression
Hypotheses prlngpln.l L = Line 𝒢 G
prlngpln.e No typesetting found for |- E = ( PlnG ` G ) with typecode |-
prlngpln.p No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
prlngpln.g φ G V
prlngpln.1 φ A ˙ B
prlngpln.2 φ A B
Assertion prlngpln φ h ran E A h B h

Proof

Step Hyp Ref Expression
1 prlngpln.l L = Line 𝒢 G
2 prlngpln.e Could not format E = ( PlnG ` G ) : No typesetting found for |- E = ( PlnG ` G ) with typecode |-
3 prlngpln.p Could not format .|| = ( parlnG ` G ) : No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
4 prlngpln.g φ G V
5 prlngpln.1 φ A ˙ B
6 prlngpln.2 φ A B
7 1 2 3 4 brprlng φ A ˙ B A ran L B ran L A = B h ran E A h B h A B =
8 5 7 mpbid φ A ran L B ran L A = B h ran E A h B h A B =
9 8 simprd φ A = B h ran E A h B h A B =
10 6 neneqd φ ¬ A = B
11 9 10 orcnd φ h ran E A h B h A B =
12 11 simpld φ h ran E A h B h