Metamath Proof Explorer


Theorem prodeq12rdv

Description: Equality deduction for product. (Contributed by Scott Fenton, 4-Dec-2017)

Ref Expression
Hypotheses prodeq12rdv.1 ⊢ φ → A = B
prodeq12rdv.2 ⊢ φ ∧ k ∈ B → C = D
Assertion prodeq12rdv ⊢ φ → ∏ k ∈ A C = ∏ k ∈ B D

Proof

Step Hyp Ref Expression
1 prodeq12rdv.1 ⊢ φ → A = B
2 prodeq12rdv.2 ⊢ φ ∧ k ∈ B → C = D
3 1 prodeq1d ⊢ φ → ∏ k ∈ A C = ∏ k ∈ B C
4 2 prodeq2dv ⊢ φ → ∏ k ∈ B C = ∏ k ∈ B D
5 3 4 eqtrd ⊢ φ → ∏ k ∈ A C = ∏ k ∈ B D