Metamath Proof Explorer


Theorem recnperf

Description: Both RR and CC are perfect subsets of CC . (Contributed by Mario Carneiro, 28-Dec-2016)

Ref Expression
Hypothesis recnperf.k ⊢ K = TopOpen ⁡ ℂ fld
Assertion recnperf ⊢ S ∈ ℝ ℂ → K ↾ 𝑡 S ∈ Perf

Proof

Step Hyp Ref Expression
1 recnperf.k ⊢ K = TopOpen ⁡ ℂ fld
2 elpri ⊢ S ∈ ℝ ℂ → S = ℝ ∨ S = ℂ
3 oveq2 ⊢ S = ℝ → K ↾ 𝑡 S = K ↾ 𝑡 ℝ
4 1 reperf ⊢ K ↾ 𝑡 ℝ ∈ Perf
5 3 4 eqeltrdi ⊢ S = ℝ → K ↾ 𝑡 S ∈ Perf
6 oveq2 ⊢ S = ℂ → K ↾ 𝑡 S = K ↾ 𝑡 ℂ
7 1 cnfldtopon ⊢ K ∈ TopOn ⁡ ℂ
8 7 toponunii ⊢ ℂ = ⋃ K
9 8 restid ⊢ K ∈ TopOn ⁡ ℂ → K ↾ 𝑡 ℂ = K
10 7 9 ax-mp ⊢ K ↾ 𝑡 ℂ = K
11 1 cnperf ⊢ K ∈ Perf
12 10 11 eqeltri ⊢ K ↾ 𝑡 ℂ ∈ Perf
13 6 12 eqeltrdi ⊢ S = ℂ → K ↾ 𝑡 S ∈ Perf
14 5 13 jaoi ⊢ S = ℝ ∨ S = ℂ → K ↾ 𝑡 S ∈ Perf
15 2 14 syl ⊢ S ∈ ℝ ℂ → K ↾ 𝑡 S ∈ Perf