Metamath Proof Explorer


Theorem reim0

Description: The imaginary part of a real number is 0. (Contributed by NM, 18-Mar-2005) (Revised by Mario Carneiro, 7-Nov-2013)

Ref Expression
Assertion reim0 ⊢ A ∈ ℝ → ℑ ⁡ A = 0

Proof

Step Hyp Ref Expression
1 recn ⊢ A ∈ ℝ → A ∈ ℂ
2 it0e0 ⊢ i ⋅ 0 = 0
3 2 oveq2i ⊢ A + i ⋅ 0 = A + 0
4 addrid ⊢ A ∈ ℂ → A + 0 = A
5 3 4 eqtrid ⊢ A ∈ ℂ → A + i ⋅ 0 = A
6 1 5 syl ⊢ A ∈ ℝ → A + i ⋅ 0 = A
7 6 fveq2d ⊢ A ∈ ℝ → ℑ ⁡ A + i ⋅ 0 = ℑ ⁡ A
8 0re ⊢ 0 ∈ ℝ
9 crim ⊢ A ∈ ℝ ∧ 0 ∈ ℝ → ℑ ⁡ A + i ⋅ 0 = 0
10 8 9 mpan2 ⊢ A ∈ ℝ → ℑ ⁡ A + i ⋅ 0 = 0
11 7 10 eqtr3d ⊢ A ∈ ℝ → ℑ ⁡ A = 0