Metamath Proof Explorer


Theorem releq

Description: Equality theorem for the relation predicate. (Contributed by NM, 1-Aug-1994)

Ref Expression
Assertion releq A=BRelARelB

Proof

Step Hyp Ref Expression
1 sseq1 A=BAV×VBV×V
2 df-rel RelAAV×V
3 df-rel RelBBV×V
4 1 2 3 3bitr4g A=BRelARelB