Metamath Proof Explorer


Theorem releq

Description: Equality theorem for the relation predicate. (Contributed by NM, 1-Aug-1994)

Ref Expression
Assertion releq A = B Rel A Rel B

Proof

Step Hyp Ref Expression
1 sseq1 A = B A V × V B V × V
2 df-rel Rel A A V × V
3 df-rel Rel B B V × V
4 1 2 3 3bitr4g A = B Rel A Rel B