Metamath Proof Explorer


Theorem relss

Description: Subclass theorem for relation predicate. Theorem 2 of Suppes p. 58. (Contributed by NM, 15-Aug-1994)

Ref Expression
Assertion relss ABRelBRelA

Proof

Step Hyp Ref Expression
1 sstr2 ABBV×VAV×V
2 df-rel RelBBV×V
3 df-rel RelAAV×V
4 1 2 3 3imtr4g ABRelBRelA