Metamath Proof Explorer


Theorem relssdmrn

Description: A relation is included in the Cartesian product of its domain and range. Exercise 4.12(t) of Mendelson p. 235. (Contributed by NM, 3-Aug-1994) (Proof shortened by SN, 23-Dec-2024)

Ref Expression
Assertion relssdmrn ⊢ Rel ⁡ A → A ⊆ dom ⁡ A × ran ⁡ A

Proof

Step Hyp Ref Expression
1 id ⊢ Rel ⁡ A → Rel ⁡ A
2 vex ⊢ x ∈ V
3 vex ⊢ y ∈ V
4 2 3 opeldm ⊢ x y ∈ A → x ∈ dom ⁡ A
5 2 3 opelrn ⊢ x y ∈ A → y ∈ ran ⁡ A
6 4 5 opelxpd ⊢ x y ∈ A → x y ∈ dom ⁡ A × ran ⁡ A
7 6 a1i ⊢ Rel ⁡ A → x y ∈ A → x y ∈ dom ⁡ A × ran ⁡ A
8 1 7 relssdv ⊢ Rel ⁡ A → A ⊆ dom ⁡ A × ran ⁡ A