Metamath Proof Explorer


Theorem relssdv

Description: Deduction from subclass principle for relations. (Contributed by NM, 11-Sep-2004)

Ref Expression
Hypotheses relssdv.1 ⊢ φ → Rel ⁡ A
relssdv.2 ⊢ φ → x y ∈ A → x y ∈ B
Assertion relssdv ⊢ φ → A ⊆ B

Proof

Step Hyp Ref Expression
1 relssdv.1 ⊢ φ → Rel ⁡ A
2 relssdv.2 ⊢ φ → x y ∈ A → x y ∈ B
3 2 alrimivv ⊢ φ → ∀ x ∀ y x y ∈ A → x y ∈ B
4 ssrel ⊢ Rel ⁡ A → A ⊆ B ↔ ∀ x ∀ y x y ∈ A → x y ∈ B
5 1 4 syl ⊢ φ → A ⊆ B ↔ ∀ x ∀ y x y ∈ A → x y ∈ B
6 3 5 mpbird ⊢ φ → A ⊆ B