Metamath Proof Explorer


Theorem remuld

Description: Real part of a product. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypotheses recld.1 ⊢ φ → A ∈ ℂ
readdd.2 ⊢ φ → B ∈ ℂ
Assertion remuld ⊢ φ → ℜ ⁡ A ⁢ B = ℜ ⁡ A ⁢ ℜ ⁡ B − ℑ ⁡ A ⁢ ℑ ⁡ B

Proof

Step Hyp Ref Expression
1 recld.1 ⊢ φ → A ∈ ℂ
2 readdd.2 ⊢ φ → B ∈ ℂ
3 remul ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℜ ⁡ A ⁢ B = ℜ ⁡ A ⁢ ℜ ⁡ B − ℑ ⁡ A ⁢ ℑ ⁡ B
4 1 2 3 syl2anc ⊢ φ → ℜ ⁡ A ⁢ B = ℜ ⁡ A ⁢ ℜ ⁡ B − ℑ ⁡ A ⁢ ℑ ⁡ B