Metamath Proof Explorer


Theorem rereccli

Description: Closure law for reciprocal. (Contributed by NM, 30-Apr-2005)

Ref Expression
Hypotheses redivcl.1 ⊢ A ∈ ℝ
rereccl.2 ⊢ A ≠ 0
Assertion rereccli ⊢ 1 A ∈ ℝ

Proof

Step Hyp Ref Expression
1 redivcl.1 ⊢ A ∈ ℝ
2 rereccl.2 ⊢ A ≠ 0
3 1 rerecclzi ⊢ A ≠ 0 → 1 A ∈ ℝ
4 2 3 ax-mp ⊢ 1 A ∈ ℝ