Metamath Proof Explorer


Theorem ricsym

Description: Ring isomorphism is symmetric. (Contributed by SN, 10-Jan-2025)

Ref Expression
Assertion ricsym ⊢ R ≃ 𝑟 S → S ≃ 𝑟 R

Proof

Step Hyp Ref Expression
1 brric ⊢ R ≃ 𝑟 S ↔ R RingIso S ≠ ∅
2 n0 ⊢ R RingIso S ≠ ∅ ↔ ∃ f f ∈ R RingIso S
3 rimcnv ⊢ f ∈ R RingIso S → f -1 ∈ S RingIso R
4 brrici ⊢ f -1 ∈ S RingIso R → S ≃ 𝑟 R
5 3 4 syl ⊢ f ∈ R RingIso S → S ≃ 𝑟 R
6 5 exlimiv ⊢ ∃ f f ∈ R RingIso S → S ≃ 𝑟 R
7 2 6 sylbi ⊢ R RingIso S ≠ ∅ → S ≃ 𝑟 R
8 1 7 sylbi ⊢ R ≃ 𝑟 S → S ≃ 𝑟 R