Metamath Proof Explorer


Theorem ricsym

Description: Ring isomorphism is symmetric. (Contributed by SN, 10-Jan-2025)

Ref Expression
Assertion ricsym ( 𝑅 ≃𝑟 𝑆 → 𝑆 ≃𝑟 𝑅 )

Proof

Step Hyp Ref Expression
1 brric ⊢ ( 𝑅 ≃𝑟 𝑆 ↔ ( 𝑅 RingIso 𝑆 ) ≠ ∅ )
2 n0 ⊢ ( ( 𝑅 RingIso 𝑆 ) ≠ ∅ ↔ ∃ 𝑓 𝑓 ∈ ( 𝑅 RingIso 𝑆 ) )
3 rimcnv ⊢ ( 𝑓 ∈ ( 𝑅 RingIso 𝑆 ) → ◡ 𝑓 ∈ ( 𝑆 RingIso 𝑅 ) )
4 brrici ⊢ ( ◡ 𝑓 ∈ ( 𝑆 RingIso 𝑅 ) → 𝑆 ≃𝑟 𝑅 )
5 3 4 syl ⊢ ( 𝑓 ∈ ( 𝑅 RingIso 𝑆 ) → 𝑆 ≃𝑟 𝑅 )
6 5 exlimiv ⊢ ( ∃ 𝑓 𝑓 ∈ ( 𝑅 RingIso 𝑆 ) → 𝑆 ≃𝑟 𝑅 )
7 2 6 sylbi ⊢ ( ( 𝑅 RingIso 𝑆 ) ≠ ∅ → 𝑆 ≃𝑟 𝑅 )
8 1 7 sylbi ⊢ ( 𝑅 ≃𝑟 𝑆 → 𝑆 ≃𝑟 𝑅 )