Metamath Proof Explorer


Theorem rlmsub

Description: Subtraction in the ring module. (Contributed by Thierry Arnoux, 30-Jun-2019)

Ref Expression
Assertion rlmsub ⊢ - R = - ringLMod ⁡ R

Proof

Step Hyp Ref Expression
1 rlmbas ⊢ Base R = Base ringLMod ⁡ R
2 1 a1i ⊢ ⊤ → Base R = Base ringLMod ⁡ R
3 rlmplusg ⊢ + R = + ringLMod ⁡ R
4 3 a1i ⊢ ⊤ → + R = + ringLMod ⁡ R
5 2 4 grpsubpropd ⊢ ⊤ → - R = - ringLMod ⁡ R
6 5 mptru ⊢ - R = - ringLMod ⁡ R