Metamath Proof Explorer


Theorem rspc2va

Description: 2-variable restricted specialization, using implicit substitution. (Contributed by NM, 18-Jun-2014)

Ref Expression
Hypotheses rspc2v.1 ⊢ x = A → φ ↔ χ
rspc2v.2 ⊢ y = B → χ ↔ ψ
Assertion rspc2va ⊢ A ∈ C ∧ B ∈ D ∧ ∀ x ∈ C ∀ y ∈ D φ → ψ

Proof

Step Hyp Ref Expression
1 rspc2v.1 ⊢ x = A → φ ↔ χ
2 rspc2v.2 ⊢ y = B → χ ↔ ψ
3 1 2 rspc2v ⊢ A ∈ C ∧ B ∈ D → ∀ x ∈ C ∀ y ∈ D φ → ψ
4 3 imp ⊢ A ∈ C ∧ B ∈ D ∧ ∀ x ∈ C ∀ y ∈ D φ → ψ