Metamath Proof Explorer


Theorem rxp112d

Description: Real exponentiation is one-to-one with respect to the second argument. (TODO: Note that the base C must be positive since -u C ^ A is C ^ A x.e ^ i _pi A , so in the negative case A = B + 2 k ). (Contributed by SN, 25-Apr-2025)

Ref Expression
Hypotheses rxp112d.c ⊢ φ → C ∈ ℝ +
rxp112d.a ⊢ φ → A ∈ ℝ
rxp112d.b ⊢ φ → B ∈ ℝ
rxp112d.1 ⊢ φ → C ≠ 1
rxp112d.2 ⊢ φ → C A = C B
Assertion rxp112d ⊢ φ → A = B

Proof

Step Hyp Ref Expression
1 rxp112d.c ⊢ φ → C ∈ ℝ +
2 rxp112d.a ⊢ φ → A ∈ ℝ
3 rxp112d.b ⊢ φ → B ∈ ℝ
4 rxp112d.1 ⊢ φ → C ≠ 1
5 rxp112d.2 ⊢ φ → C A = C B
6 2 recnd ⊢ φ → A ∈ ℂ
7 3 recnd ⊢ φ → B ∈ ℂ
8 1 relogcld ⊢ φ → log ⁡ C ∈ ℝ
9 8 recnd ⊢ φ → log ⁡ C ∈ ℂ
10 1 4 logne0d ⊢ φ → log ⁡ C ≠ 0
11 5 fveq2d ⊢ φ → log ⁡ C A = log ⁡ C B
12 1 2 logcxpd ⊢ φ → log ⁡ C A = A ⁢ log ⁡ C
13 1 3 logcxpd ⊢ φ → log ⁡ C B = B ⁢ log ⁡ C
14 11 12 13 3eqtr3d ⊢ φ → A ⁢ log ⁡ C = B ⁢ log ⁡ C
15 6 7 9 10 14 mulcan2ad ⊢ φ → A = B