Metamath Proof Explorer


Theorem sbcied

Description: Conversion of implicit substitution to explicit class substitution, deduction form. (Contributed by NM, 13-Dec-2014) Avoid ax-10 , ax-12 . (Revised by GG, 12-Oct-2024)

Ref Expression
Hypotheses sbcied.1 ⊢ φ → A ∈ V
sbcied.2 ⊢ φ ∧ x = A → ψ ↔ χ
Assertion sbcied ⊢ φ → [˙A / x]˙ ψ ↔ χ

Proof

Step Hyp Ref Expression
1 sbcied.1 ⊢ φ → A ∈ V
2 sbcied.2 ⊢ φ ∧ x = A → ψ ↔ χ
3 df-sbc ⊢ [˙A / x]˙ ψ ↔ A ∈ x | ψ
4 1 2 elabd3 ⊢ φ → A ∈ x | ψ ↔ χ
5 3 4 bitrid ⊢ φ → [˙A / x]˙ ψ ↔ χ