Metamath Proof Explorer


Theorem sgn0

Description: The signum of 0 is 0. (Contributed by David A. Wheeler, 15-May-2015)

Ref Expression
Assertion sgn0 sgn0=0

Proof

Step Hyp Ref Expression
1 0xr 0*
2 sgnval 0*sgn0=if0=00if0<011
3 1 2 ax-mp sgn0=if0=00if0<011
4 eqid 0=0
5 4 iftruei if0=00if0<011=0
6 3 5 eqtri sgn0=0