Metamath Proof Explorer


Theorem sgn0

Description: The signum of 0 is 0. (Contributed by David A. Wheeler, 15-May-2015)

Ref Expression
Assertion sgn0 sgn 0 = 0

Proof

Step Hyp Ref Expression
1 0xr 0 *
2 sgnval 0 * sgn 0 = if 0 = 0 0 if 0 < 0 1 1
3 1 2 ax-mp sgn 0 = if 0 = 0 0 if 0 < 0 1 1
4 eqid 0 = 0
5 4 iftruei if 0 = 0 0 if 0 < 0 1 1 = 0
6 3 5 eqtri sgn 0 = 0