Metamath Proof Explorer


Theorem spc2egv

Description: Existential specialization with two quantifiers, using implicit substitution. (Contributed by NM, 3-Aug-1995)

Ref Expression
Hypothesis spc2egv.1 ⊢ x = A ∧ y = B → φ ↔ ψ
Assertion spc2egv ⊢ A ∈ V ∧ B ∈ W → ψ → ∃ x ∃ y φ

Proof

Step Hyp Ref Expression
1 spc2egv.1 ⊢ x = A ∧ y = B → φ ↔ ψ
2 elisset ⊢ A ∈ V → ∃ x x = A
3 elisset ⊢ B ∈ W → ∃ y y = B
4 2 3 anim12i ⊢ A ∈ V ∧ B ∈ W → ∃ x x = A ∧ ∃ y y = B
5 exdistrv ⊢ ∃ x ∃ y x = A ∧ y = B ↔ ∃ x x = A ∧ ∃ y y = B
6 4 5 sylibr ⊢ A ∈ V ∧ B ∈ W → ∃ x ∃ y x = A ∧ y = B
7 1 biimprcd ⊢ ψ → x = A ∧ y = B → φ
8 7 2eximdv ⊢ ψ → ∃ x ∃ y x = A ∧ y = B → ∃ x ∃ y φ
9 6 8 syl5com ⊢ A ∈ V ∧ B ∈ W → ψ → ∃ x ∃ y φ