Metamath Proof Explorer


Theorem spcev

Description: Existential specialization, using implicit substitution. (Contributed by NM, 31-Dec-1993) (Proof shortened by Eric Schmidt, 22-Dec-2006)

Ref Expression
Hypotheses spcv.1 ⊢ A ∈ V
spcv.2 ⊢ x = A → φ ↔ ψ
Assertion spcev ⊢ ψ → ∃ x φ

Proof

Step Hyp Ref Expression
1 spcv.1 ⊢ A ∈ V
2 spcv.2 ⊢ x = A → φ ↔ ψ
3 2 spcegv ⊢ A ∈ V → ψ → ∃ x φ
4 1 3 ax-mp ⊢ ψ → ∃ x φ