Metamath Proof Explorer


Theorem spei

Description: Inference from existential specialization, using implicit substitution. Remove a distinct variable constraint. Usage of this theorem is discouraged because it depends on ax-13 . Use the weaker speiv if possible. (Contributed by NM, 19-Aug-1993) (Proof shortened by Wolf Lammen, 12-May-2018) (New usage is discouraged.)

Ref Expression
Hypotheses spei.1 ⊢ x = y → φ ↔ ψ
spei.2 ⊢ ψ
Assertion spei ⊢ ∃ x φ

Proof

Step Hyp Ref Expression
1 spei.1 ⊢ x = y → φ ↔ ψ
2 spei.2 ⊢ ψ
3 ax6e ⊢ ∃ x x = y
4 2 1 mpbiri ⊢ x = y → φ
5 3 4 eximii ⊢ ∃ x φ