Metamath Proof Explorer


Theorem spesbc

Description: Existence form of spsbc . (Contributed by Mario Carneiro, 18-Nov-2016)

Ref Expression
Assertion spesbc ⊢ [˙A / x]˙ φ → ∃ x φ

Proof

Step Hyp Ref Expression
1 sbcex ⊢ [˙A / x]˙ φ → A ∈ V
2 rspesbca ⊢ A ∈ V ∧ [˙A / x]˙ φ → ∃ x ∈ V φ
3 1 2 mpancom ⊢ [˙A / x]˙ φ → ∃ x ∈ V φ
4 rexv ⊢ ∃ x ∈ V φ ↔ ∃ x φ
5 3 4 sylib ⊢ [˙A / x]˙ φ → ∃ x φ