Metamath Proof Explorer


Theorem spv

Description: Specialization, using implicit substitution. Usage of this theorem is discouraged because it depends on ax-13 . Use the weaker spvv if possible. (Contributed by NM, 30-Aug-1993) (New usage is discouraged.)

Ref Expression
Hypothesis spv.1 ⊢ x = y → φ ↔ ψ
Assertion spv ⊢ ∀ x φ → ψ

Proof

Step Hyp Ref Expression
1 spv.1 ⊢ x = y → φ ↔ ψ
2 1 biimpd ⊢ x = y → φ → ψ
3 2 spimv ⊢ ∀ x φ → ψ