Metamath Proof Explorer


Theorem spv

Description: Specialization, using implicit substitution. Usage of this theorem is discouraged because it depends on ax-13 . Use the weaker spvv if possible. (Contributed by NM, 30-Aug-1993) (New usage is discouraged.)

Ref Expression
Hypothesis spv.1 x=yφψ
Assertion spv xφψ

Proof

Step Hyp Ref Expression
1 spv.1 x=yφψ
2 1 biimpd x=yφψ
3 2 spimv xφψ