Metamath Proof Explorer


Theorem sqrt2gt1lt2

Description: The square root of 2 is bounded by 1 and 2. (Contributed by Roy F. Longton, 8-Aug-2005) (Revised by Mario Carneiro, 6-Sep-2013)

Ref Expression
Assertion sqrt2gt1lt2 ⊢ 1 < 2 ∧ 2 < 2

Proof

Step Hyp Ref Expression
1 sqrt1 ⊢ 1 = 1
2 1lt2 ⊢ 1 < 2
3 1re ⊢ 1 ∈ ℝ
4 0le1 ⊢ 0 ≤ 1
5 2re ⊢ 2 ∈ ℝ
6 0le2 ⊢ 0 ≤ 2
7 sqrtlt ⊢ 1 ∈ ℝ ∧ 0 ≤ 1 ∧ 2 ∈ ℝ ∧ 0 ≤ 2 → 1 < 2 ↔ 1 < 2
8 3 4 5 6 7 mp4an ⊢ 1 < 2 ↔ 1 < 2
9 2 8 mpbi ⊢ 1 < 2
10 1 9 eqbrtrri ⊢ 1 < 2
11 2lt4 ⊢ 2 < 4
12 4re ⊢ 4 ∈ ℝ
13 0re ⊢ 0 ∈ ℝ
14 4pos ⊢ 0 < 4
15 13 12 14 ltleii ⊢ 0 ≤ 4
16 sqrtlt ⊢ 2 ∈ ℝ ∧ 0 ≤ 2 ∧ 4 ∈ ℝ ∧ 0 ≤ 4 → 2 < 4 ↔ 2 < 4
17 5 6 12 15 16 mp4an ⊢ 2 < 4 ↔ 2 < 4
18 11 17 mpbi ⊢ 2 < 4
19 sqrt4 ⊢ 4 = 2
20 18 19 breqtri ⊢ 2 < 2
21 10 20 pm3.2i ⊢ 1 < 2 ∧ 2 < 2