Metamath Proof Explorer


Theorem sqrtqaa

Description: Square root of a rational number is algebraic. (Contributed by Ender Ting, 22-Jul-2026)

Ref Expression
Assertion sqrtqaa ⊢ A ∈ ℚ → A ∈ 𝔸

Proof

Step Hyp Ref Expression
1 fveq2 ⊢ A = 0 → A = 0
2 sqrt0 ⊢ 0 = 0
3 1 2 eqtrdi ⊢ A = 0 → A = 0
4 0aa ⊢ 0 ∈ 𝔸
5 3 4 eqeltrdi ⊢ A = 0 → A ∈ 𝔸
6 5 adantl ⊢ A ∈ ℚ ∧ A = 0 → A ∈ 𝔸
7 sqrtnzqaa ⊢ A ∈ ℚ ∧ A ≠ 0 → A ∈ 𝔸
8 6 7 pm2.61dane ⊢ A ∈ ℚ → A ∈ 𝔸