Metamath Proof Explorer


Theorem sqxpexg

Description: The Cartesian square of a set is a set. (Contributed by AV, 13-Jan-2020)

Ref Expression
Assertion sqxpexg ⊢ A ∈ V → A × A ∈ V

Proof

Step Hyp Ref Expression
1 xpexg ⊢ A ∈ V ∧ A ∈ V → A × A ∈ V
2 1 anidms ⊢ A ∈ V → A × A ∈ V