Metamath Proof Explorer


Theorem sscres

Description: Any function restricted to a square domain is a subcategory subset of the original. (Contributed by Mario Carneiro, 6-Jan-2017)

Ref Expression
Assertion sscres ⊢ H Fn S × S ∧ S ∈ V → H ↾ T × T ⊆ cat H

Proof

Step Hyp Ref Expression
1 inss1 ⊢ S ∩ T ⊆ S
2 simpl ⊢ x ∈ S ∩ T ∧ y ∈ S ∩ T → x ∈ S ∩ T
3 2 elin2d ⊢ x ∈ S ∩ T ∧ y ∈ S ∩ T → x ∈ T
4 simpr ⊢ x ∈ S ∩ T ∧ y ∈ S ∩ T → y ∈ S ∩ T
5 4 elin2d ⊢ x ∈ S ∩ T ∧ y ∈ S ∩ T → y ∈ T
6 3 5 ovresd ⊢ x ∈ S ∩ T ∧ y ∈ S ∩ T → x H ↾ T × T y = x H y
7 eqimss ⊢ x H ↾ T × T y = x H y → x H ↾ T × T y ⊆ x H y
8 6 7 syl ⊢ x ∈ S ∩ T ∧ y ∈ S ∩ T → x H ↾ T × T y ⊆ x H y
9 8 rgen2 ⊢ ∀ x ∈ S ∩ T ∀ y ∈ S ∩ T x H ↾ T × T y ⊆ x H y
10 1 9 pm3.2i ⊢ S ∩ T ⊆ S ∧ ∀ x ∈ S ∩ T ∀ y ∈ S ∩ T x H ↾ T × T y ⊆ x H y
11 simpl ⊢ H Fn S × S ∧ S ∈ V → H Fn S × S
12 inss1 ⊢ S × S ∩ T × T ⊆ S × S
13 fnssres ⊢ H Fn S × S ∧ S × S ∩ T × T ⊆ S × S → H ↾ S × S ∩ T × T Fn S × S ∩ T × T
14 11 12 13 sylancl ⊢ H Fn S × S ∧ S ∈ V → H ↾ S × S ∩ T × T Fn S × S ∩ T × T
15 resres ⊢ H ↾ S × S ↾ T × T = H ↾ S × S ∩ T × T
16 fnresdm ⊢ H Fn S × S → H ↾ S × S = H
17 16 adantr ⊢ H Fn S × S ∧ S ∈ V → H ↾ S × S = H
18 17 reseq1d ⊢ H Fn S × S ∧ S ∈ V → H ↾ S × S ↾ T × T = H ↾ T × T
19 15 18 eqtr3id ⊢ H Fn S × S ∧ S ∈ V → H ↾ S × S ∩ T × T = H ↾ T × T
20 inxp ⊢ S × S ∩ T × T = S ∩ T × S ∩ T
21 20 a1i ⊢ H Fn S × S ∧ S ∈ V → S × S ∩ T × T = S ∩ T × S ∩ T
22 19 21 fneq12d ⊢ H Fn S × S ∧ S ∈ V → H ↾ S × S ∩ T × T Fn S × S ∩ T × T ↔ H ↾ T × T Fn S ∩ T × S ∩ T
23 14 22 mpbid ⊢ H Fn S × S ∧ S ∈ V → H ↾ T × T Fn S ∩ T × S ∩ T
24 simpr ⊢ H Fn S × S ∧ S ∈ V → S ∈ V
25 23 11 24 isssc ⊢ H Fn S × S ∧ S ∈ V → H ↾ T × T ⊆ cat H ↔ S ∩ T ⊆ S ∧ ∀ x ∈ S ∩ T ∀ y ∈ S ∩ T x H ↾ T × T y ⊆ x H y
26 10 25 mpbiri ⊢ H Fn S × S ∧ S ∈ V → H ↾ T × T ⊆ cat H