Metamath Proof Explorer


Theorem sseld

Description: Membership deduction from subclass relationship. (Contributed by NM, 15-Nov-1995)

Ref Expression
Hypothesis sseld.1 ⊢ φ → A ⊆ B
Assertion sseld ⊢ φ → C ∈ A → C ∈ B

Proof

Step Hyp Ref Expression
1 sseld.1 ⊢ φ → A ⊆ B
2 ssel ⊢ A ⊆ B → C ∈ A → C ∈ B
3 1 2 syl ⊢ φ → C ∈ A → C ∈ B