Metamath Proof Explorer


Theorem sselda

Description: Membership deduction from subclass relationship. (Contributed by NM, 26-Jun-2014)

Ref Expression
Hypothesis sseld.1 φAB
Assertion sselda φCACB

Proof

Step Hyp Ref Expression
1 sseld.1 φAB
2 1 sseld φCACB
3 2 imp φCACB