Metamath Proof Explorer


Theorem sselda

Description: Membership deduction from subclass relationship. (Contributed by NM, 26-Jun-2014)

Ref Expression
Hypothesis sseld.1 φ A B
Assertion sselda φ C A C B

Proof

Step Hyp Ref Expression
1 sseld.1 φ A B
2 1 sseld φ C A C B
3 2 imp φ C A C B